Fortran: simplification of FINDLOC for constant complex arguments [PR110585]
gcc/fortran/ChangeLog: PR fortran/110585 * arith.cc (gfc_compare_expr): Handle equality comparison of constant complex gfc_expr arguments. gcc/testsuite/ChangeLog: PR fortran/110585 * gfortran.dg/findloc_9.f90: New test. (cherry picked from commit 7ac1581d066a6f3a0d4acf1042a74634258b4966)
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@ -1120,6 +1120,11 @@ gfc_compare_expr (gfc_expr *op1, gfc_expr *op2, gfc_intrinsic_op op)
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|| (op1->value.logical && !op2->value.logical));
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break;
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case BT_COMPLEX:
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gcc_assert (op == INTRINSIC_EQ);
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rc = mpc_cmp (op1->value.complex, op2->value.complex);
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break;
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default:
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gfc_internal_error ("gfc_compare_expr(): Bad basic type");
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}
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19
gcc/testsuite/gfortran.dg/findloc_9.f90
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19
gcc/testsuite/gfortran.dg/findloc_9.f90
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@ -0,0 +1,19 @@
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! { dg-do compile }
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! { dg-options "-fdump-tree-original" }
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! PR fortran/110585 - simplification of FINDLOC for constant complex arguments
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program mvce
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implicit none
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integer, parameter :: a(*) = findloc([(1.,0.),(2.,1.)], (2.,0.))
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integer, parameter :: b(*) = findloc([(1.,0.),(2.,1.)], (2.,0.), back=.true.)
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integer, parameter :: c(*) = findloc([(1.,0.),(2.,1.)], (2.,1.))
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integer, parameter :: d(*) = findloc([(1.,0.),(2.,1.)], (2.,1.), back=.true.)
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integer, parameter :: e = findloc([(1.,0.),(2.,1.)], (2.,1.), dim=1)
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if (a(1) /= 0) stop 1
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if (b(1) /= 0) stop 2
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if (c(1) /= 2) stop 3
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if (d(1) /= 2) stop 4
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if (e /= 2) stop 5
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end
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! { dg-final { scan-tree-dump-not "_gfortran_stop_numeric" "original" } }
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